Both Liverpool and Leicester City head into Saturday's Premier League clash without any new injury concerns.

Jürgen Klopp’s Reds make the journey to the King Power Stadium as the division’s early leaders three games into the campaign, having beaten West Ham United, Crystal Palace and Brighton and Hove Albion without conceding a goal.

Dejan Lovren (pelvis) remains unavailable, while Rhian Brewster and Alex Oxlade-Chamberlain are, of course, long-term injury absentees.

But Klopp has the rest of the squad at his disposal against the Foxes.

The manager named the same starting line-up in each of Liverpool’s previous three fixtures this term but explained why a long week of training provided a chance for others to stake a claim before the trip.

“In a week like this, when we have at least three very intense sessions, I’m pretty open to everybody,” he said.

“I want to see who shows me the most and who shows me that he’s so desperate to play. Of course there is a little advantage for the line-up last week which won the game, but that’s the only thing. I’m really open.

“And what fits to the opponent, what is needed for the opponent, is very important. It’s not that I closed the book already directly after the game and thought: ‘OK, we won again so they will play again if nothing happens.’ No.”

It is a similar situation for Leicester boss Claude Puel, who confirmed on Thursday that Matty James (Achilles) is the only player ruled out of his team due to injury.

Jamie Vardy is also unavailable for the hosts, however – the striker is suspended after receiving a red card in the Foxes’ 2-0 victory over Wolverhampton Wanderers earlier this month.

That win was the first of three in a row for Puel’s side ahead of Liverpool’s visit.

Last time out

Leicester v Fleetwood Town, August 28: Ward, Amartey, Morgan, Evans, Fuchs, Iborra, Silva, Ghezzal, Okazaki, Albrighton, Iheanacho.

Liverpool v Brighton and Hove Albion, August 25: Alisson, Alexander-Arnold, Gomez, Van Dijk, Robertson, Wijnaldum, Milner, Keita, Salah, Mane, Firmino.